Administrators Teddy Posted July 19, 2024 Administrators Posted July 19, 2024 A user recently asked "How do I implement a hyperbolic tangent function in Seeq?"
Administrators Solution Teddy Posted July 19, 2024 Author Administrators Solution Posted July 19, 2024 Unfortunately, Seeq does not support the hyperbolic tangent function directly. However, it does support the exponential function so re-creating the hyperbolic tangent function is fairly simple. The formula below can be used to achieve the same result as a tanh or hyperbolic tangent. (Constant.E ^ (2*$x )- 1)/(Constant.E ^(2*$x) + 1) Note: To create and exponent in Seeq (e^x) you need to use Constant.E^x.
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