spy.jobs.schedule

[Ruby Han]

Hello,

I am trying to express "every 1st saturday of the month" for spy.jobs.schedule(). Referenced site: https://www.freeformatter.com/cron-expression-generator-quartz.html based on helper doc string but gave me an error as shown below.

 

Thanks in advance for the help!

Ruby Han

[Joe Reckamp]

Hi Ruby,

This should work instead:

spy.jobs.schedule('0 0 0 ? * 6#1 *')

 

Edited September 1, 2022 by Joe Reckamp

[Ruby Han]

Thank you for the quick response! To go one step further, how do I express "every 1st saturday of the month at 1am"?

[Joe Reckamp]

You just would change the third value to a 1:

spy.jobs.schedule('0 0 1 ? * 6#1 *')

 

[Ruby Han]

Great, that work! Thanks!

[Ruby Han]

I'm receiving an error for scheduling every 1st sunday of the month.

[Chris Orr]

Ruby, 

Sunday is the 0th day of the week in the cron scheduler so: 

spy.jobs.schedule('0 0 1 ? * 0#1 *')

[Ruby Han]

Awesome, thank you!